Motor Plants and Auxiliary Boilers: A four cylinder, four-stroke cycle, single acting diesel engine has a 740 mm bor...

Discussing this exam question.

gi gigem_das05 · May 25, 2017 9:36pm

I don't think this question is correct. Every time I calculate I come up with answer B 4644KW.

Ar Artemis17 · May 29, 2017 8:56pm

This answer is correct. IHP=(4 CYL)(18kg/cm2)(9.81m/s2)(10,000cm2/m2)(1.5m)(pi*.74^2/4)(90/2)

gi gigem_das05 · May 30, 2017 3:04am

I used IHP = (PLAN*n/2)/4500, where P = pressure in kg/cm^2, L = length in meter, A is area in cm^2, N = RPM, n = # of cylinders. 4500 conversion factor for kW and HP.
I appreciate the feedback but I am not following your math and when I used your calculation I got a huge number. Could you offer a little more detail. Thanks

Ar Artemis17 · May 30, 2017 6:22am

There isn't really a conversion factor for kW, only HP. IHP=PLAN will yield W so you simply divide by 1000 to convert to kW. Also, I apologize, I forgot to write (1/60) to convert RPM to seconds above, but that will get you the correct answer "3416".