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Engine: Motor Plants and Auxiliary Boilers

Question 1,339 of 947

A four cylinder, four-stroke cycle, single acting diesel engine has a 740 mm bore and a 1500 mm stroke. What indicated power will be developed if the average mean effective pressure is 18 kg/cm2 at a speed of 90 RPM?

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Comments from mariners who studied this question.

gi gigem_das05 · May 25, 2017
I don't think this question is correct. Every time I calculate I come up with answer B 4644KW.
Ar Artemis17 · May 29, 2017
This answer is correct. IHP=(4 CYL)(18kg/cm2)(9.81m/s2)(10,000cm2/m2)(1.5m)(pi*.74^2/4)(90/2)
gi gigem_das05 · May 30, 2017
I used IHP = (PLAN*n/2)/4500, where P = pressure in kg/cm^2, L = length in meter, A is area in cm^2, N = RPM, n = # of cylinders. 4500 conversion factor for kW and HP.
I appreciate the feedback but I am not following your math and when I used your calculation I got a huge number. Could you offer a little more detail. Thanks
Ar Artemis17 · May 30, 2017
There isn't really a conversion factor for kW, only HP. IHP=PLAN will yield W so you simply divide by 1000 to convert to kW. Also, I apologize, I forgot to write (1/60) to convert RPM to seconds above, but that will get you the correct answer "3416".