I = P/V, 500,000W/480V = 1041.xx (0.9) = 937.5
Engine
Electricity: From the information given in the illustration, what would be the maximum output...
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yeah i'm getting the same thing. answer is A
P=SQR(3)xIxVxPF
500000=1.73xIx480X0.9
i=500000/1.73x480x0.9
i=669 Amps
500000=1.73xIx480X0.9
i=500000/1.73x480x0.9
i=669 Amps